Matrix user forums

Dear All:

For memory addressing, we need High and Low Bytes, as see the datasheet of memory, this devise have a 256kb this mean that we have 4096 readings, is it right?, then how can I address the individual register to obtain 4096 registers
(xxxBytes H and xxxBytes L ?)

Thanks

AG

Hi,

You have 256k bits of data, this means 256 * 1024 = 262144 bits, this means 32768 bytes (starting from 0 to 32767).
So you can write data from 0000 (hex value) to 7FFF (hex value).

To write a byte to address 1234h (example), you'll first need to send a control byte (see datasheet).
Then you'll need to send the higher 8 bits (12h) of the address and then the lower 8 bits (34h) of the address to the EEPROM.
Once that's done, you can send your byte.

PS: Don't forget the startbit and stopbit.

I did use a 24FC1025 EEPROM before, it is used almost the same way as the 24LC256.
Here's a link to the article on my webpage : http://pyroesp.x10.mx/PIC/post3.html

Regards,

Nicolas Lopez F.